 |
|
|
|
SCHOOL SUBJECTS
-
-
-
-
-
-
-
-
-
-
-
-
|
|
|
GRADE LEVELS
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
|
|
|
|
Post a New Question | Current Questions | Chat With Live Tutors
Homework Help Forum: algebra
Posted by Brett on Wednesday, November 4, 2009 at 7:54pm.
|
how do i factor 8m^2-6mn-9n^2
|
- algebra - Reiny, Wednesday, November 4, 2009 at 8:26pm
If you had
8x^2 - 6x - 9 can you see how I factored it to
(4x+3)(2x-3) ?
|
- algebra - suseela.R, Wednesday, November 4, 2009 at 11:36pm
8x^2 - 6x - 9
For this problem we have to multiply the first and the last term here the first term is 8 and the last term is -9 if we multiplied this two we will get -72 then we have to split this number in to two parts and the multiplication value of splitted term must be equal to -72 and the simplification value must be equal to the midlle term that is -6 .So we can split 72 as (-12)*6
8x^2-6x-9 = (2x-3)(4x+3)
|
Answer this Question
For Further Reading
|
|
|
 |