Posted by **julie** on Wednesday, November 4, 2009 at 6:15pm.

can someone please tell me how to solve these, thanks!

1.2(3b-4)=8b-11

2.5(r-1)=2(r-4)-6

3.2y+3=3(y+7)

4.15x-10=-9x+2

- algebra -
**Lisa**, Wednesday, November 4, 2009 at 6:23pm
1.2(3b-4)=8b-11

6b-8 = 8b-11

-2b = -3

b = 3/2

- algebra -
**julie**, Wednesday, November 4, 2009 at 6:26pm
i don't get it :( at all

- algebra -
**Lisa**, Wednesday, November 4, 2009 at 6:28pm
3. 2y+3 = 3(y+7)

2y+3 = 3y+21

-y = 18

y = -18

I have helped you on # 1 and 3, now I think you can manage doing 2 and 4.

- algebra -
**Lisa**, Wednesday, November 4, 2009 at 6:31pm
for # 3, you can use the distributive property.

2y+3=3(y+7)

2y+3 = 3y+21

subtract 2y from both sides of the equation

3 = y+21

now subtract 21 from both sides

-18 =y

- algebra -
**Lisa**, Wednesday, November 4, 2009 at 6:33pm
4. 15x -10 =-9x+2

15x +9x = 2+10

24x = 12

x = 1/2

- algebra -
**julie**, Wednesday, November 4, 2009 at 6:36pm
ohhh i get it thanks!

- algebra -
**Lisa**, Wednesday, November 4, 2009 at 6:38pm
I'm really glad you do, and you're welcome;)

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