algebra
posted by julie on .
can someone please tell me how to solve these, thanks!
1.2(3b4)=8b11
2.5(r1)=2(r4)6
3.2y+3=3(y+7)
4.15x10=9x+2

1.2(3b4)=8b11
6b8 = 8b11
2b = 3
b = 3/2 
i don't get it :( at all

3. 2y+3 = 3(y+7)
2y+3 = 3y+21
y = 18
y = 18
I have helped you on # 1 and 3, now I think you can manage doing 2 and 4. 
for # 3, you can use the distributive property.
2y+3=3(y+7)
2y+3 = 3y+21
subtract 2y from both sides of the equation
3 = y+21
now subtract 21 from both sides
18 =y 
4. 15x 10 =9x+2
15x +9x = 2+10
24x = 12
x = 1/2 
ohhh i get it thanks!

I'm really glad you do, and you're welcome;)