Posted by julie on Wednesday, November 4, 2009 at 6:15pm.
can someone please tell me how to solve these, thanks!
1.2(3b4)=8b11
2.5(r1)=2(r4)6
3.2y+3=3(y+7)
4.15x10=9x+2

algebra  Lisa, Wednesday, November 4, 2009 at 6:23pm
1.2(3b4)=8b11
6b8 = 8b11
2b = 3
b = 3/2

algebra  julie, Wednesday, November 4, 2009 at 6:26pm
i don't get it :( at all

algebra  Lisa, Wednesday, November 4, 2009 at 6:28pm
3. 2y+3 = 3(y+7)
2y+3 = 3y+21
y = 18
y = 18
I have helped you on # 1 and 3, now I think you can manage doing 2 and 4.

algebra  Lisa, Wednesday, November 4, 2009 at 6:31pm
for # 3, you can use the distributive property.
2y+3=3(y+7)
2y+3 = 3y+21
subtract 2y from both sides of the equation
3 = y+21
now subtract 21 from both sides
18 =y

algebra  Lisa, Wednesday, November 4, 2009 at 6:33pm
4. 15x 10 =9x+2
15x +9x = 2+10
24x = 12
x = 1/2

algebra  julie, Wednesday, November 4, 2009 at 6:36pm
ohhh i get it thanks!

algebra  Lisa, Wednesday, November 4, 2009 at 6:38pm
I'm really glad you do, and you're welcome;)
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