If P (A) = 2/3 (two thirds), P (B) = 1/6(one sixth), P (A and B) = 0, 16 what can you say about P (A or B)?
That P is either two thirds or zero?
P(2/3 or 0)?
Pb is 1/4 of Pa if that helps, but i don't really understand what you or maybe the question is asking
It is saying
P(A)= two thirds 2/3
P(B)= one sixth 1/6
P(A and B)= 0
So what is P ( A or B )
I honestly don't understand either, well obviously or I wouldn't have had to ask. :)
To determine the probability of the union of two events, P(A or B), you can use the formula:
P(A or B) = P(A) + P(B) - P(A and B)
Given that P(A) = 2/3, P(B) = 1/6, and P(A and B) = 0.16 (or 16/100), we can substitute these values into the formula:
P(A or B) = 2/3 + 1/6 - 16/100
Simplifying the expression:
P(A or B) = 2/3 + 1/6 - 16/100
= 4/6 + 1/6 - 16/100
= 5/6 - 16/100
To perform the subtraction, we need a common denominator. Let's find the least common multiple (LCM) of 6 and 100, which is 300:
P(A or B) = (5/6) * (50/50) - (16/100) * (3/3)
= 250/300 - 48/300
= (250 - 48) / 300
= 202 / 300
Simplifying the fraction:
P(A or B) = 101 / 150
Therefore, the probability P(A or B) is 101/150, which is not equal to two-thirds or zero.