Arrange the following from the most work to the least. For each instance, calculate the total amount of work done. Show all calculations, including units of measure.

1. pushing a box of math books weighing 600 newtons a distance of 20 meters
12000J

2. pulling a television weighing 400 newtons down a hallway of 35 meters
14000J
3. pushing a stalled truck weighing 7,500 newtons a distance of 0.4 meters
3000J
4. carrying several textbooks weighing 130 newtons, over the course of a semester, for 5,000 meters
650000J
i am quite confused... would it be 4,2,1,3 or is that wrong? and why?

None of these do work. Is the weight in the direction of the movement? Ans: No

all are wrong.

i did all those calculations...so are the calculations wrong or is there just no order period cause none do work?

To determine the amount of work for each instance, we can use the formula: Work = force * distance * cos(theta) where theta is the angle between the force and the direction of motion (which is 0 degrees in this case since we are assuming the force is applied in the same direction as the motion).

Let's calculate the work for each instance:

1. Pushing a box of math books weighing 600 newtons a distance of 20 meters:
Work = 600 N * 20 m * cos(0 degrees) = 12,000 Joules

2. Pulling a television weighing 400 newtons down a hallway of 35 meters:
Work = 400 N * 35 m * cos(0 degrees) = 14,000 Joules

3. Pushing a stalled truck weighing 7,500 newtons a distance of 0.4 meters:
Work = 7,500 N * 0.4 m * cos(0 degrees) = 3,000 Joules

4. Carrying several textbooks weighing 130 newtons, over the course of a semester, for 5,000 meters:
Work = 130 N * 5,000 m * cos(0 degrees) = 650,000 Joules

Now let's arrange them from most work to least work:

1. Carrying several textbooks: 650,000 Joules
2. Pulling a television: 14,000 Joules
3. Pushing a box of math books: 12,000 Joules
4. Pushing a stalled truck: 3,000 Joules

So the correct order, from most work to least work, is: 4, 2, 1, 3.