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November 28, 2014

November 28, 2014

Posted by **Nikita** on Wednesday, November 4, 2009 at 1:15pm.

1) Differentiate both sides with respect to x

2) Realize that y is a function of x

3) Solve for y

Plus the d/dx notation made it even more confusing. Can someone please explain this to me simply? Thanks

- Calculus -
**bobpursley**, Wednesday, November 4, 2009 at 1:24pmhttp://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/implicitdiffdirectory/ImplicitDiff.html

That is an excellent discussion.

Here is an example:

x^3 + xy^2 + x^2 y=14 find dy/dx

by implicit diff:

3x^2 dx/dx + y^2 dx/dx + 2yxdy/dx +2xydx/dx+x^2 dy/dx=0

butdx/dx is one, so

3x^2+y^2+2xy + dy/dx (2xy+x^2)=0

so dy/dx=-(3x^2+y^3 +2xy)/(2xy-x^2)

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