For a machine with an efficiency of 80%, what is the work output of the machine if its work input is 2,000 joules?

would i divide 2000/.80? which gives me 2500?

Also,
If a machine requires an effort force of 750 newtons applied over a distance of 2 meters, over what resistance distance is the machine acting if the resistance force has a value of 150 newtons? Assume that it is an ideal machine. (HINT: Use the equation Fe x de = F r x dr)
A 5 meters
B 10 meters
C 150 meters
D 300 meters

can you help me set up the equation cause im lossttt! please(:

No to your first question. You can't get more work out than you put in.

Second question: For a 100% efficient machine, the product of force x distance is the same for the input (effort) as the output (resistance). That is the equation they told you to use. So, use it. You want to solve for the resistance distance dr

dr = Fe*de/Fr = 750*2/150 = ? meters

so would i mult. 2000* .80 which gives me 1600?

This doesnt answer my question can someone on here please answer me question i am having a really hard time with my test in cyberschool

Yes, you are on the right track with the first question. To find the work output of the machine, you need to divide the work input by the efficiency. In this case, the work input is 2,000 joules and the efficiency is 80%. To calculate the work output, you can use the formula:

Work Output = Work Input / Efficiency

Substituting the given values:

Work Output = 2000 joules / 0.80

Dividing 2000 joules by 0.80 gives you a work output of 2500 joules.

Now, let's move on to the second question. To solve this problem, you need to use the equation Fe x de = Fr x dr, which relates the effort force (Fe), effort distance (de), resistance force (Fr), and resistance distance (dr).

In this case, you are given the effort force (Fe) of 750 newtons, the effort distance (de) of 2 meters, and the resistance force (Fr) of 150 newtons. You need to find the resistance distance (dr).

The equation can be rearranged as:

dr = (Fe x de) / Fr

Substituting the given values:

dr = (750 newtons x 2 meters) / 150 newtons

Multiplying 750 newtons by 2 meters gives you 1500 newton-meters. Dividing 1500 newton-meters by 150 newtons gives you a resistance distance of 10 meters.

Therefore, the answer is B) 10 meters.