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Homework Help Forum: Physics
Posted by Corey on Wednesday, November 4, 2009 at 12:39pm.
fully loaded, slow-moving freight elevator has a cab with a total mass of 1250 kg, which is required to travel upward 58 m in 3.4 min, starting and ending at rest. The elevator's counterweight has a mass of only 1005 kg, and so the elevator motor must help. What average power is required of the force the motor exerts on the cab via the cable?
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- Physics - bobpursley, Wednesday, November 4, 2009 at 12:59pm
The lifting force is (1250-1005)g
or force=245g
power=work/time=245*58/(3.4*60)
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