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March 27, 2017

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fully loaded, slow-moving freight elevator has a cab with a total mass of 1250 kg, which is required to travel upward 58 m in 3.4 min, starting and ending at rest. The elevator's counterweight has a mass of only 1005 kg, and so the elevator motor must help. What average power is required of the force the motor exerts on the cab via the cable?
________W

  • Physics - ,

    The lifting force is (1250-1005)g

    or force=245g

    power=work/time=245*58/(3.4*60)

  • Physics - ,

    force of gravity on elevator is

    1250 kg * 9.8= 12250 N

    Force of counter weight is

    1005 kg * 9.8= 9849 N

    12250 N - 9849 N = 2761 N Total

    P = (F*d)/T

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