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December 19, 2014

December 19, 2014

Posted by **Adrian** on Wednesday, November 4, 2009 at 2:23am.

x³-8x²+11x+20

- math -
**Reiny**, Wednesday, November 4, 2009 at 7:51amtry some factors of 20

I tried ±1 and sure enough -1 worked, so x+1 is a factor

Then by either long division or synthetic division of x³-8x²+11x+20 by x+1

we would get x^2 - 9x + 20

which factors again into (x-4)(x-5)

so x³-8x²+11x+20 = (x+1)x-4)(x-5)

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