Homework Help Forum: algebra 1

Posted by Anonymous on Wednesday, November 4, 2009 at 12:16am.

14x+3x-40=11

• algebra 1 - Lynn, Wednesday, November 4, 2009 at 3:54am

  Add the 14x and the 3x = 17x now you have 17x-40=11 you have to get the plain numbers on one side of the = sign and the number with letters on the other side. Since it shows that you are subtracting the 40 you have to add 40 to each side. 17x-40+40=11+40 (-40+40=0) (11+40=51) 17x=51 now divide the number next to the letter into both sides 17x/17 and 51/17 leaves you with x=3 14x+3x-40=11 17x-40=11 17x-40+40=11+40 17x=51 x=3

  
  

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