Posted by **Adrienne ** on Tuesday, November 3, 2009 at 10:09pm.

A speed velocity of a a rocket with a mass of 0.25 kg passes from 15 m/s[up] to 40 m/s[up] in 0.60s. calculate the force of the escaped gasses of the rocket.

****

that's what i've done, so far

data: m = 0.25kg

initial velocity = 15 m/s

final velocity = 40 m/s

time = 0.60s

final velocity - initial velocity / time = acceleration

40 m/s - 15 m/s / 0.60 s = 41.67 m/s^2

for here the solutions for the problem says that the next formula that needs to be used is FORCE = MASS (GRAVITY + ACCELERATION) why is that.

and why would you not use the formula

force = mass x acceleration ?

## Answer this Question

## Related Questions

- physics 20 - A speed velocity of a a rocket with a mass of 0.25 kg passes from ...
- Physics - A rocket of mass 1.0x10^3kg is being fired to a height of 5.0 x 10^3 m...
- Physics - I have to design a procedure which allows me to calculate the applied ...
- Physics - A rocket was launched and it now has an acceleration of 3m pers second...
- Physics - With the engines off, a spaceship is coasting at a velocity of +210 m/...
- physics - A rocket burns 5kg per ejecting it as a gas with a velocity of 1600m/s...
- physics - A rocket with mass of 60,000 kg is placed on a launching platform ...
- Physics - With the engines off, a spaceship is coasting at avelocity of +260m/s ...
- Physics - A small rocket is fired in a test range. It rises high into the air ...
- physics - if a rocket engine delivers a constant thrust, does it deliver more ...

More Related Questions