Tuesday

March 31, 2015

March 31, 2015

Posted by **Josh** on Tuesday, November 3, 2009 at 9:18pm.

F=(GmM)/r^2

Here G is the gravitational constant and r is the distance between the bodies.

(a) Find dF/dr

(b) Suppose it is known that Earth attracts an object with a force that decreases at the rate of 2 N/km when r = 30,000 km. How fast does this force change when r = 15,000 km?

- Calc -
**bobpursley**, Tuesday, November 3, 2009 at 9:24pmdF/dr=-2GMm/r^3=-2F/r

b) dF/dr=-2 when r=30,000

but the relationship is inverse, so halving the distance will double the rate.

- Calc -
**Garrett**, Monday, October 10, 2011 at 8:59pm16

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