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Post a New Question | Current Questions | Chat With Live Tutors
Posted by Shane on Tuesday, November 3, 2009 at 9:11pm.
Calculate the velocity of a satellite moving in a stable circular orbit about the Earth at a height of 2600 km.
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- physics - forces - bobpursley, Tuesday, November 3, 2009 at 9:16pm
Fgravity=Fcentripetal
GMearth/(radEarth+ 2600km)^2= mv^2/(radearth+2600)
solve for v.
change all distances to meters..
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- physics - forces - Shane, Tuesday, November 3, 2009 at 9:21pm
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would m be the mass of the earth?
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- physics - forces - bobpursley, Tuesday, November 3, 2009 at 9:27pm
m is mass satellite.
And I forgot one on the left of that line.
Here is is corrected:
GMearth*m/(radEarth+ 2600km)^2= mv^2/(radearth+2600)
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- physics - forces - Anonymous, Tuesday, November 3, 2009 at 9:38pm
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does that mean the mass of the statellite cancels? because the mass of the statellite isnt given
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- physics - forces - bobpursley, Tuesday, November 3, 2009 at 9:49pm
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yes, the mass of the satellite divides out.
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