Posted by **Sasha** on Tuesday, November 3, 2009 at 8:39pm.

a child sitting 1.10 m from the center of a merry go round moves with a speed of 1.25 m/s. calculate the centripetal acceleration of the child and the net horizontal force exerted on the child (mass = 25 kg).

- PHYSICS -
**drwls**, Tuesday, November 3, 2009 at 9:05pm
The centripetal acceleration is

a = V^2/R and the force is

F = m a = m V^2/R.

m = 25 kg

V = 1.25 m/s

R = 1.10 m

Do the numbers.

- PHYSICS -
**Sasha**, Tuesday, November 3, 2009 at 9:18pm
so i did a = 1.25^/1.1 = 1.42 m/s^2

then F =ma = 25(1.42) = 35.5N is that right?

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