Homework Help Forum: Algebra

Posted by Anneliese on Tuesday, November 3, 2009 at 8:09pm.

How do you find the zeroes of the 1/2x^3-x? I factoried it so it would be 1/2x(x^2)-x. The one zero would then be zero, which matches with my book's answer. But I have no idea how my book got +/- the sq. root of two for the other one. Can you demonstrate, please?

• Algebra - Reiny, Tuesday, November 3, 2009 at 8:21pm

  The way you factored makes no sense to me> Your factors should be x((1/2)x^2 - 1) so x = 0 or (1/2)x^2 - 1 = 0 x^2 = 2 then x = ±√2

  
  

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