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March 4, 2015

March 4, 2015

Posted by **Javier** on Tuesday, November 3, 2009 at 7:22pm.

- 5th grade-math -
**bobpursley**, Tuesday, November 3, 2009 at 7:41pmq=D-2

.25q+ .10D=1.95

.25(D-2)+.10D=1.95

.25D-.50+.10D=1.95

add .50 to each side.

.35D=2.45

solve for D by dividing each side by .35

then q= D-2

- 5th grade-math -
**Quidditch**, Tuesday, November 3, 2009 at 7:42pmLet d = the number of dimes.

Let q = the number of quarters.

What is known...

d * $0.10 + q * $0.25 = $1.95

and...

q = d - 2

Substitute the above equation for q into the first equation. That gives an equation only in d. Solve for d. Then plug that value into the second equation to find q.

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