Posted by **Javier** on Tuesday, November 3, 2009 at 7:22pm.

Sheila brought $1.95 in coins to spend at the bake sale. Her coins were all in dimes and quarters. The number of quarters she had was two less than the number of dimes. How many of each coin did she have?.

- 5th grade-math -
**bobpursley**, Tuesday, November 3, 2009 at 7:41pm
q=D-2

.25q+ .10D=1.95

.25(D-2)+.10D=1.95

.25D-.50+.10D=1.95

add .50 to each side.

.35D=2.45

solve for D by dividing each side by .35

then q= D-2

- 5th grade-math -
**Quidditch**, Tuesday, November 3, 2009 at 7:42pm
Let d = the number of dimes.

Let q = the number of quarters.

What is known...

d * $0.10 + q * $0.25 = $1.95

and...

q = d - 2

Substitute the above equation for q into the first equation. That gives an equation only in d. Solve for d. Then plug that value into the second equation to find q.

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