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March 6, 2015

Posted by **Confused** on Tuesday, November 3, 2009 at 9:52am.

N = t^2 + 12t + 54

- Math -
**Reiny**, Tuesday, November 3, 2009 at 10:05amSomething is not right about your equation.

The way it is, it would be a parabola opening upwards, and of course it would not have a maximum, but rather a minimum value of N

Are you sure the first term wasn't -t^2 ?

- Math -
**drwls**, Tuesday, November 3, 2009 at 10:11amI assume you don't know calculus, so you will have to use the "completing the square" technique (or graphing) to find the t value for which N is greatest.

N = t^2 + 12t + 54

= t^2 + 12t + 36 + 18

= (t+6)^2 + 18

That is SMALLEST when t = -6. I assume you are only interested in t>0. There is no maximum. Are you sure you didn't mean to write

N = t^2 - 12t + 54 ?

- Math -
**Confused**, Tuesday, November 3, 2009 at 4:18pmSorry, Yes the correct equation is

-t^2 + 12t + 54

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