Homework Help Forum: calculus - antiderivative

Posted by thomas on Tuesday, November 3, 2009 at 12:06am.

can someone help me find the antiderivative of: f'(x) = (x^2-1)/x where f(1)=1/2, and f(-1) = 0 Thanks!

• calculus - antiderivative - drwls, Tuesday, November 3, 2009 at 2:08am

  f'(x) = x - 1/x Integrate one term at a time. f(x) = x^2/2 - ln x + C If f(1) = 1/2, then C = 0 (for x>0 only) I'm not sure how to handle the f(-1) = 0 case. You can't take a log of a negative number.

  
  

Answer this Question

First Name:
School Subject:
Answer:

For Further Reading