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August 29, 2014

August 29, 2014

Posted by **thomas** on Tuesday, November 3, 2009 at 12:06am.

f'(x) = (x^2-1)/x where f(1)=1/2, and f(-1) = 0

Thanks!

- calculus - antiderivative -
**drwls**, Tuesday, November 3, 2009 at 2:08amf'(x) = x - 1/x

Integrate one term at a time.

f(x) = x^2/2 - ln x + C

If f(1) = 1/2, then C = 0

(for x>0 only)

I'm not sure how to handle the f(-1) = 0 case. You can't take a log of a negative number.

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