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Posted by on Sunday, November 1, 2009 at 8:18pm.

What are the first and second derivatives of y = (1/x^2)-(1/(x-2)^2)?

  • calc - , Sunday, November 1, 2009 at 9:09pm

    I will do the first...

    y'= -2/x^3 - dy/dx (1/(x-2)^2)=
    = -2/x^3 +2/(x-1)^3
    check that.

  • calc - , Sunday, November 1, 2009 at 9:21pm

    Yes, that is what I got as well. So would we have to go further, or does that suffice? Thank you.

  • calc - , Sunday, November 1, 2009 at 9:44pm

    But isn't it supposed to be 2/x^3 - 2/(x-2)^3?

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