Posted by Freddy on Sunday, November 1, 2009 at 8:18pm.
What are the first and second derivatives of y = (1/x^2)(1/(x2)^2)?

calc  bobpursley, Sunday, November 1, 2009 at 9:09pm
I will do the first...
y'= 2/x^3  dy/dx (1/(x2)^2)=
= 2/x^3 +2/(x1)^3
check that.

calc  Neil, Sunday, November 1, 2009 at 9:21pm
Yes, that is what I got as well. So would we have to go further, or does that suffice? Thank you.

calc  Freddy, Sunday, November 1, 2009 at 9:44pm
But isn't it supposed to be 2/x^3  2/(x2)^3?
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