What are the first and second derivatives of y = (1/x^2)-(1/(x-2)^2)?
I will do the first...
y'= -2/x^3 - dy/dx (1/(x-2)^2)=
= -2/x^3 +2/(x-1)^3
Yes, that is what I got as well. So would we have to go further, or does that suffice? Thank you.
But isn't it supposed to be 2/x^3 - 2/(x-2)^3?