in 1995 the life expectancy of males in a certain country was 68.7 yrs in 2000 it was 71.3 yrs let E repressent the life expectancy in yrs T and let T represent the the number of yrs since 1995.

the linear function e (t) that fits the data is e (t)=T+ round to the nearest tenth to perdict the life expetacny of males in 2003 e (8)=
please help

To find the predicted life expectancy of males in 2003 using the linear function e(t), we need to substitute the value of t, which represents the number of years since 1995, into the equation.

Given that the life expectancy in 1995 was 68.7 years and in 2000 was 71.3 years, we can determine the change in life expectancy over a 5-year period.

Change in life expectancy = 71.3 years - 68.7 years = 2.6 years

Since each year represents 1 unit of time (t) in this case, the change in life expectancy over 5 years is 2.6 years. Therefore, the rate of change (slope) of the linear function is:

Rate of change (m) = Change in life expectancy / Change in time = 2.6 years / 5 years = 0.52 years per year

So, now we have the slope of the linear function e(t), which is 0.52 years per year. We also know that in 1995 the life expectancy was 68.7 years.

Therefore, the linear function e(t) can be written as:

e(t) = 0.52t + 68.7

To find the predicted life expectancy in 2003 (8 years after 1995), substitute t = 8 into the equation:

e(8) = 0.52 * 8 + 68.7

Now, calculate the value:

e(8) = 4.16 + 68.7

e(8) = 72.86

Therefore, the predicted life expectancy of males in 2003 is approximately 72.9 years.