Tuesday

July 29, 2014

July 29, 2014

Posted by **Anonymous** on Sunday, November 1, 2009 at 7:42pm.

a) Construct a 95% confidence interval estimate for the population mean the price for 2 tickets with online service charges, large popcorn and 2 medium soft drinks, assuming a normal distribution.

mean of sample = 36.53

n = 6

standard deviation = 19.26866 ( square root of ((36.15 - 36.53)^2 + (31 - 36.53)^2 + (35.05 - 36.53)^2 + (40.25 - 36.53)^2 + (33.75 - 36.53)^2 + (43 - 36.53)^2) / 6-1)

standard error of sample mean = 7.8664

critical value of t = 0.025

degrees of freedom = 5

95% C.I. = 36.53 +/- (critical value of t = 0.025)(7.8664)

95% C.I. = 36.53 +/- (2.571)(7.8664)

95% C.I. = 36.53 +/- 20.2245

My answer is wrong and the interval estimate is between 31.9267 and 41.1399. I think my error is solving for the standard deviation. How do you solve for it? Please provide a step-by-step solution. Thank you.

**Related Questions**

Algerba - THe senior class is raising money by selling popcorn amd soft drinks. ...

Discrete Mathematics - When a theater charges $50 per ticket, a sold-out crowd ...

math - 30% of the tickets sold by a movie theater for the Friday night show were...

Algebra - A movie theater manager wants to know how many adults and how many ...

math - for an annual fee of $30 you can join a movie club that will allow you to...

ratio - 30% of the tickets sold by a movie theater for the Friday night show ...

Math - Four friends went to see a movie. Each ticket cost $x. The table shows ...

Math - A 3500-seat theater sells tickets for $75 and $110. Each night the ...

math - a 6,000 seat theater has tickets for sale at $26 and $40 . How many ...

Algebra - The twin theater charges $7 for adult tickets and $4 for children 12 ...