a 22.5g sample of (NH4)2CO3 (ammonium carbonate) contains _____ moles of ammonium ions?

it contains 0.288ol of ammonium ions

grams/molar mass = moles (NH4)2CO3. Then there are two MH4^+ per molecule of (NH4)2CO3.

To determine the number of moles of ammonium ions in (NH4)2CO3, we need to look at the formula of the compound.

The formula (NH4)2CO3 tells us that there are 2 ammonium ions (NH4+) in the compound.

To calculate the number of moles, we can use the formula:

moles = mass / molar mass

The molar mass of (NH4)2CO3 can be calculated by adding up the individual molar masses of each element in the compound:

Molar mass of (NH4)2CO3 = (2 * molar mass of NH4) + molar mass of C + (3 * molar mass of O)

The molar mass of NH4 is:

1 nitrogen (N) atom = 1 * 14.01 g/mol = 14.01 g/mol
4 hydrogen (H) atoms = 4 * 1.01 g/mol = 4.04 g/mol

So the molar mass of NH4 is 14.01 g/mol + 4.04 g/mol = 18.05 g/mol.

The molar mass of C is 12.01 g/mol, and the molar mass of O is 16.00 g/mol.

Now, we can calculate the molar mass of (NH4)2CO3:

Molar mass of (NH4)2CO3 = (2 * 18.05 g/mol) + 12.01 g/mol + (3 * 16.00 g/mol) = 96.09 g/mol

Now, we can calculate the number of moles of (NH4)2CO3 using the given mass of the sample:

moles = 22.5 g / 96.09 g/mol = 0.234 moles

Since there are 2 ammonium ions in each formula unit of (NH4)2CO3, the sample contains:

0.234 moles * 2 = 0.468 moles of ammonium ions

Therefore, a 22.5 g sample of (NH4)2CO3 contains 0.468 moles of ammonium ions.

To find the number of moles of ammonium ions in a given sample of (NH4)2CO3 (ammonium carbonate), we need to first calculate the molar mass of (NH4)2CO3 and then use the formula:

moles = mass / molar mass

Let's break down the molar mass calculation:

The molar mass of (NH4)2CO3 can be determined by adding up the atomic masses of all the individual atoms:

[(2 × molar mass of NH4) + molar mass of CO3]

The molar mass of NH4 (ammonium) can be found by adding up the atomic masses of nitrogen (N) and hydrogen (H):

molar mass of NH4 = (molar mass of N) + (molar mass of H) × 4

Finally, we add up the contributions from the ammonium and carbonate components to find the molar mass of (NH4)2CO3.

Once we have calculated the molar mass, we can then use the given mass of the sample to calculate the number of moles of (NH4)2CO3, considering the molar mass as a conversion factor.

Therefore, to determine the number of moles of ammonium ions in the 22.5g sample of (NH4)2CO3, we need to calculate the molar mass of (NH4)2CO3 using the steps above and then divide the given mass by the molar mass.