find the indicated out puts for f (x)=5x^-2x

f(0)=
f(-1)=
f(2)=

I will be happy to check your work. These are incredibly easy, is there something you don't understand on how to do them?

I don't understand how it works im not good at algebra any help i would like ty

would f(0)=1

f(-1)=-2
f(2)=3

any help please

To find the indicated outputs for the function f(x) = 5x^(-2x), you simply need to substitute the given values of x into the function and calculate the result. Let's find the indicated outputs step by step:

1. f(0):
To find f(0), substitute 0 for x in the function:
f(0) = 5(0)^(-2(0))

Since any number (except zero) raised to the power of zero is equal to 1, we have:
f(0) = 5(0^0)

However, 0^0 is an indeterminate form, which means its value is not well-defined. It is best to avoid defining 0^0 as a specific value in most cases. Therefore, the indicated output for f(0) is undefined.

2. f(-1):
To find f(-1), substitute -1 for x in the function:
f(-1) = 5(-1)^(-2(-1))
= 5(-1)^(2)
= 5(1)
= 5

So, the indicated output for f(-1) is 5.

3. f(2):
To find f(2), substitute 2 for x in the function:
f(2) = 5(2)^(-2(2))
= 5(2)^(-4)
= 5/(2^4)
= 5/16

Therefore, the indicated output for f(2) is 5/16.

To summarize:
f(0) is undefined,
f(-1) = 5,
f(2) = 5/16.