Monday

March 30, 2015

March 30, 2015

Posted by **alison** on Sunday, November 1, 2009 at 12:52pm.

I found the deriviative to be (x-2)/(3-y)

Then, the x value for a horizontal would be x=2 and the y value for a vertical would be y=3.

But how do i find the exact points. My teacher gave me these answers

Horizontal tangent at (2,8) and (2,-2)

Vertical tangent at (7,3) and (-3,3)

But i dont understand how she got those points. can someone show me?

Thanks

- math -
**jim**, Sunday, November 1, 2009 at 1:42pmYou've done the hard part, so you're probably just over-thinking it! :-)

When x=2, plug 2 into that equation of the circle, and what do you get?

x^2 -4x + y^2 -6y =12

4 - 8 + y^2 -6y = 12

y^2 -6y -16 = 0

and solve for y.

Same method works for getting the points where y=3.

**Answer this Question**

**Related Questions**

kaley - find the points at which the graph of 4x^2 - 4x + 12y^2 -6y = 10 has a ...

calculus - find the points at which the graph of 4x^2 - 4x + 12y^2 -6y = 10 has ...

Calculus - 55. Find an equation of the tangent line to the graph of f(x) =x^3 - ...

math - For the given function, find all points on an the graph where the tangent...

Calculus - Given the function y=(x^2-5/x+3), answer the following questions. a) ...

Calculus - Suppose f(x)= e^(-1/x). Graph this function in the window -5(</=)x...

Calculus - Suppose f(x)= e^(-1/x). Graph this function in the window -5(</=)x...

calculus - Find dy/dx 4x^2+y^2-8x+4y+4=0, find points on graph of the equation ...

math - Note: y^1 means the deriviative of... If f(2)=3 and y^1(2)=5 find an ...

calculus - find the points on a graph of f where the tangent line is horizontal...