Tuesday

March 31, 2015

March 31, 2015

Posted by **Anonymous** on Saturday, October 31, 2009 at 9:26pm.

- physics -
**drwls**, Sunday, November 1, 2009 at 9:48amUse a conservation of energy method.

Initial KE + gravitational PE loss = spring potential energy.

(1/2) (m + M) Vo^2 + (m + M) g H = (1/2) k X^2

Vo is the initial velocity after getting onto the bobsled. It is less than 14.7 m/s, because there will be some inelastic energy loss hopping on. You will have to use conservation of momentum to compute Vo.

m*(14.7) = Vo*(M+m)

H is the vertical distance her bobsled slides before hitting the spring, 46.0 m * sin 21.

m is her mass (40 kg), M is the bobsled mass (20.8 kg), and g is the acceleration of gravity.

Solve for X

**Answer this Question**

**Related Questions**

physics - A new event has been proposed for the Winter Olympics. An athlete will...

Physics - A 75.0kg bobsled is pushed along a horizontal surface by two athletes...

Physics - A 79.4 kg bobsled is pushed along a horizontal surface by two athletes...

physics - please show me in steps how to solve this thanks alot! A bobsled zips ...

physics - A 75 kg bobsled is pushed along a horizontal surface by two athletes. ...

physics - A bobsled slides down an ice track starting (at zero initial speed) ...

physic - A bobsled slides down an ice track starting (at zero initial speed) ...

Physics - The speed of a bobsled is increasing because it has an acceleration of...

physics - The speed of a bobsled is increasing because it has an acceleration of...

physics - In the first 3.8 seconds of a bobsled run, the 57 kg sled is pushed ...