Posted by **Anonymous** on Saturday, October 31, 2009 at 9:26pm.

A new event has been proposed for the Winter Olympics. An athlete will sprint 150.0 m, starting from rest, then leap onto a 20.8 kg bobsled. The person and bobsled will then slide down a 46.0 m long ice-recovered ramp, sloped at á=21.0°, and into a spring with a carfully calibrated spring constant of 1544.0 N/m. The athlete who compresses the spring the farthest wins the gold medal. Jennifer, whose mass is 40.0 kg, has been training for this event. She can reach a maximum speed of 14.7 m/s in the 150.0 m dash. How far will Jennifer compress the spring?

- physics -
**drwls**, Sunday, November 1, 2009 at 9:48am
Use a conservation of energy method.

Initial KE + gravitational PE loss = spring potential energy.

(1/2) (m + M) Vo^2 + (m + M) g H = (1/2) k X^2

Vo is the initial velocity after getting onto the bobsled. It is less than 14.7 m/s, because there will be some inelastic energy loss hopping on. You will have to use conservation of momentum to compute Vo.

m*(14.7) = Vo*(M+m)

H is the vertical distance her bobsled slides before hitting the spring, 46.0 m * sin 21.

m is her mass (40 kg), M is the bobsled mass (20.8 kg), and g is the acceleration of gravity.

Solve for X

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