Posted by **Anonymous** on Saturday, October 31, 2009 at 3:32pm.

6)A 700kg car is travelling at a constant velocity of 35m/s when it slams on the brakes and comes to a stop. How far did the car travel during braking if the coefficient of kinetic friction is 0.62 ? (Hint: if the accelerator is no longer being pressed, is there an applied force by the engine?)

kinetic friction= μk(normal force) 35m/s = .62(700X9.8N/kg)

35m/s=.62(6860) .. is this the correct way to do it?

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