Posted by **Anonymous** on Saturday, October 31, 2009 at 3:31pm.

4) A 1200 kg car is accelerating at 1.6 m/s2. If the coefficient of friction of friction is 0.15, what is the force applied to the car by the engine?

here do you use the equation kinetic friction= μk(normal force) and put in 1.6 m/s^2=.15(Fn) is this how you go about it?

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