Posted by **kim** on Saturday, October 31, 2009 at 3:17pm.

express the complex number in standard form(that is like a+bi)

1/2+i

2+i/2-i

- precalc -
**bobpursley**, Saturday, October 31, 2009 at 3:21pm
rationalize the denominator. I will do one:

(2+i)/(2-i)= 2+i)(2+i)/(2-i)(2+i)=

(2+i)^2/(2-i^2)= (4+4i+i^2)/3

you can complete it.

- precalc -
**kim**, Saturday, October 31, 2009 at 3:34pm
so is that the final answer

- precalc -
**kim**, Saturday, October 31, 2009 at 3:36pm
os is the final answer 8i+i^3/3

- precalc -
**MathMate**, Sunday, November 1, 2009 at 11:30am
(2+i)/(2-i)

=(2+i)(2+i)/((2+i)(2-i))

=(4+4i+i²)/(2²-i²)

=(4+4i-1)/(4-(-1))

=(3+4i)/5

You can proceed along the same lines for the first problem.

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