Post a New Question


posted by .

A force F = (4.18xi + 3.18yj) N acts on an object as it moves in the x direction from the origin to x = 4.34 m. Calculate the work done on the object by the force.

  • physics -

    Work= INTEGRAL f.dx= 4.18x^2/2 at limits
    or 1/2 4.18(4.34^2) joules.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question