Homework Help: physics

Posted by Anonymous on Saturday, October 31, 2009 at 1:02pm.

When a 4.48 kg mass is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.68 cm.

How much work must an external agent do to stretch the spring 3.96 cm from its unstretched position?

physics - bobpursley, Saturday, October 31, 2009 at 1:09pm
from the mass (remember mg is weight), find the spring constant.

Work=1/2 kx^2
physics - omar, Wednesday, November 2, 2011 at 11:51am
128.45

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