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When a 4.48 kg mass is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.68 cm.

How much work must an external agent do to stretch the spring 3.96 cm from its unstretched position?

  • physics -

    from the mass (remember mg is weight), find the spring constant.

    Work=1/2 kx^2

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