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March 28, 2017

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A 190 g air-track glider is attached to a spring. The glider is pushed in 9.8 cm and released. A student with a stopwatch finds that 14 oscillations take 18.5 sec.
What is the spring constant?

  • college physics - ,

    frequency=1/2pi *sqrt(k/mass)
    and frequency is 1/period.

  • college physics - ,

    frequency= oscillations/second

    f=14osc/18.5sec=0.76Hz

    T= 1/f

    T= 2pi/w

    1/0.76Hz=2pi/w

    cross multiply

    w=2pi*0.76= 4.775 rad/s


    w=sqrt(k/m)

    square both sides

    w^2=k/m

    w^2 * m = k

    k = w^2 * m

    you have "w" and you have mass. Plug them in and find the spring constant. Don't forget to convert the mass from grams to kilograms.

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