Posted by **Dan** on Friday, October 30, 2009 at 6:26pm.

A 190 g air-track glider is attached to a spring. The glider is pushed in 9.8 cm and released. A student with a stopwatch finds that 14 oscillations take 18.5 sec.

What is the spring constant?

- college physics -
**bobpursley**, Friday, October 30, 2009 at 6:41pm
frequency=1/2pi *sqrt(k/mass)

and frequency is 1/period.

- college physics -
**Helmeppo**, Wednesday, June 5, 2013 at 6:17pm
frequency= oscillations/second

f=14osc/18.5sec=0.76Hz

T= 1/f

T= 2pi/w

1/0.76Hz=2pi/w

cross multiply

w=2pi*0.76= 4.775 rad/s

w=sqrt(k/m)

square both sides

w^2=k/m

w^2 * m = k

k = w^2 * m

you have "w" and you have mass. Plug them in and find the spring constant. Don't forget to convert the mass from grams to kilograms.

## Answer this Question

## Related Questions

- College Physics - A 220 air-track glider is attached to a spring. The glider is ...
- Physics - A 210 g air-track glider is attached to a spring. The glider is pushed...
- physic - please help me im stuck. A 400 g air-track glider attached to a spring ...
- physic - An air-track glider attached to a spring oscillates between the 3.00 cm...
- physic - please help, i have done the part a and b but i dont know how to do ...
- physics - Two air-track gliders are held together with a string. The mass of ...
- Physics - An air track glider, 8.0 cm long, blocks light as it goes through a ...
- Physics - An air track glider, 8.0 cm long, blocks light as it goes through a ...
- Physics - An air track glider, 8.0 cm long, blocks light as it goes through a ...
- Physics - An air track glider, 8.0 cm long, blocks light as it goes through a ...