Posted by Alex on Thursday, October 29, 2009 at 9:07pm.
f(t)= 2te^t^2, [0,5] Find average value.
Attempt: I know that the average value is the integration of f(t) from a to b divided by ba. I used u substitution to get u= t^2 and du= 2xdx. I
changed the limits of integration to [0,25] and I got integral of e^u du.
I am not sure if this is right, but then would the integral of that be
just e^u and I would just plug in 25, because I did that and the answer
was wrong.

Calculus  MathMate, Thursday, October 29, 2009 at 9:39pm
I don't see anything wrong with your approach. Perhaps there was an arithmetic error lurking somewhere.
What did you get for the answer?
Did you divide the integral by 5 or 25?

Calculus  Collin, Friday, October 30, 2009 at 4:25pm
You are almost right but since u=t^(2) the limits are [0,25] then put them into e^(u) and you get,
e^(25)e^(0)=
e^(25)1
Then divide that answer by 5 thus the answer is,
(e^(25)1)/5
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