Posted by Alex on Thursday, October 29, 2009 at 9:07pm.
f(t)= -2te^-t^2, [0,5] Find average value.
Attempt: I know that the average value is the integration of f(t) from a to b divided by b-a. I used u substitution to get u= -t^2 and du= -2xdx. I
changed the limits of integration to [0,25] and I got integral of e^u du.
I am not sure if this is right, but then would the integral of that be
just e^u and I would just plug in 25, because I did that and the answer
- Calculus - MathMate, Thursday, October 29, 2009 at 9:39pm
I don't see anything wrong with your approach. Perhaps there was an arithmetic error lurking somewhere.
What did you get for the answer?
Did you divide the integral by 5 or 25?
- Calculus - Collin, Friday, October 30, 2009 at 4:25pm
You are almost right but since u=-t^(2) the limits are [0,-25] then put them into e^(u) and you get,
Then divide that answer by 5 thus the answer is,
Answer This Question
More Related Questions
- Calculus - Find the average value of f(t)=-2te^(-t^2) on the interval [0,3]
- Calculus - Use the Fundamental Theorem of Calculus to find the area of the ...
- Calculus - Find the average value of the function f(x) 8x^2-9x+8 on the interval...
- calculus - is average rate of change and average value the same or will you get ...
- Calculus - What is the average value of f(x) on [0,4] if the area between the ...
- Math - Calculus - If 75100 dollars is deposited in an account for 13 years at 5....
- Calculus - a)Find the average value of f(x) = e-x over the interval [0,k] b)What...
- calculus - Find the average value of the function f(x)=8x^2-5x+6 , on the ...
- Average Value - Calculus - What is the average value of y for the part of the ...
- Calculus - A) Find the average value of f(x)=x^3-x+1 on the interval (0,2) B) ...