Thursday

October 23, 2014

October 23, 2014

Posted by **tim** on Thursday, October 29, 2009 at 8:11pm.

(2-3i)+(6+5i)

(squareroot5-3i)+(-2+squareroot-9)

- algebra II -
**MathMate**, Thursday, October 29, 2009 at 11:20pm(2-3i)+(6+5i)

=2-3i+6+5i

=2+6 -3i+5i

=8+2i

You can do the same procedure for the second part, but change √-9 into 3i before.

**Answer this Question**

**Related Questions**

Algebra - I need some help figuring these. Compute each product and simplify ...

Algebra - I need some help figuring these. Compute each product and simplify the...

calculus - write the expression in the form bi, where b is the real number ...

algebra - ^5 squareroot of x^20 *my answer x^4 ^3 squareroot of 729/343 my ...

Algebra - I need help solving the following. Perform the indicated operatioons ...

math 11 review - A couple of extra practice questions I can't remember how to do...

calculus - write the product in standard form (1-4i)(3-2i) (squareroot-4+i)(6-5i...

Algebra2 - Simplify: 1.SquareRoot(-144) 2.SquareRoot(-64x^4) 3.SquareRoot(-13)*...

7th grade math standard form scientific notation - In standard form: 5. 3.2 x 10...

mathematics - Squareroot of (0.0256/25) giving your answer in standard form. Is ...