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January 29, 2015

January 29, 2015

Posted by **Ash** on Thursday, October 29, 2009 at 6:54pm.

- calculus -
**webwork problem?**, Thursday, October 29, 2009 at 11:21pmv=1/3*pi*r^2h r=2/h

V=1/3*pi*(h/2)^2*h

=1/3*pi*h^2/4*h

=1/12*pi*h^3

V'=10ft^3/min

h=20ft

V'=1/12*pi*3h^2*h'

10=1/12*pi*3(20)^2*h'

solve for h'

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