Homework Help Forum: calculus

Posted by Ash on Thursday, October 29, 2009 at 6:53pm.

Air is being pumped into a spherical balloon so that its volume increases at a rate of 80cm^3/s. How fast is the surface area of the balloon increasing when its radius is 7cm?

• calculus - Reiny, Thursday, October 29, 2009 at 6:59pm

  V = (4/3)pi(r^3) dV/dt = 4pi(r^2)dr/dt when t=7 80 = 4pi(49)dr/dt dr/dt = 80/(196pi) SA = 4pi(r^2) d(SA)/dt = 8pi(r)dr/dt = 8pi(7)*80/(196pi) etc

  
  

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