Posted by **tommy** on Thursday, October 29, 2009 at 6:25pm.

write the expression in the form bi, where b is the real number

squareroot-16

squareroot-25

squareroot-3

squareroot-5

- calculus -
**bobpursley**, Thursday, October 29, 2009 at 6:28pm
what is 4i squared? 5i?

- calculus -
**Reiny**, Thursday, October 29, 2009 at 6:28pm
√-16

= √-1√16

= 4i

now you do the others the same way.

- calculus -
**Collin**, Friday, October 30, 2009 at 2:35pm
sqrt(-16)=sqrt(-1)sqrt(16)=i sqrt(16)=4i

sqrt(-25)=sqrt(-1)sqrt(25)=i sqrt(25)=5i

I think you can see it now. Just remember i=sqrt(-1). And don't forget your properties of sq-roots.

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