Homework Help Forum: calculus

Posted by tommy on Thursday, October 29, 2009 at 6:25pm.

write the expression in the form bi, where b is the real number squareroot-16 squareroot-25 squareroot-3 squareroot-5

• calculus - bobpursley, Thursday, October 29, 2009 at 6:28pm

  what is 4i squared? 5i?

  
  

• calculus - Reiny, Thursday, October 29, 2009 at 6:28pm

  √-16 = √-1√16 = 4i now you do the others the same way.

  
  

• calculus - tommy, Thursday, October 29, 2009 at 6:29pm

  8

  
  

• calculus - Collin, Friday, October 30, 2009 at 2:35pm

  sqrt(-16)=sqrt(-1)sqrt(16)=i sqrt(16)=4i sqrt(-25)=sqrt(-1)sqrt(25)=i sqrt(25)=5i I think you can see it now. Just remember i=sqrt(-1). And don't forget your properties of sq-roots.

  
  

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