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Homework Help Forum: calculus

Posted by tommy on Thursday, October 29, 2009 at 6:25pm.

write the expression in the form bi, where b is the real number

squareroot-16

squareroot-25

squareroot-3

squareroot-5

  • calculus - bobpursley, Thursday, October 29, 2009 at 6:28pm

    what is 4i squared? 5i?

  • calculus - Reiny, Thursday, October 29, 2009 at 6:28pm

    √-16
    = √-1√16
    = 4i

    now you do the others the same way.

  • calculus - tommy, Thursday, October 29, 2009 at 6:29pm

    8

  • calculus - Collin, Friday, October 30, 2009 at 2:35pm

    sqrt(-16)=sqrt(-1)sqrt(16)=i sqrt(16)=4i
    sqrt(-25)=sqrt(-1)sqrt(25)=i sqrt(25)=5i

    I think you can see it now. Just remember i=sqrt(-1). And don't forget your properties of sq-roots.

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