Posted by **Ash** on Thursday, October 29, 2009 at 5:38pm.

At noon, ship A is 30 nautical miles due west of ship B. Ship A is sailing west at 17 knots and ship B is sailing north at 23 knots. How fast (in knots) is the distance between the ships changing at 3 PM?

- calculus -
**Reiny**, Thursday, October 29, 2009 at 6:36pm
Let the distance between them be D n miles.

Let the time passes since noon be t hours.

Did you make a diagram?

I see a right-angles triangle with sides

(23t), (17t + 30) and D so that

D^2 = (23t)^2 + (17t + 30)^2

2D(dD/dt) = 2(23t)(23) + 2(17t+30)(17)

dD/dt = (529t + 289t + 510)/D

when t = 3, (3:00 pm)

D^2 = 4761+6561

D = 106.405

dD/dt = (529(3) + 289(3) +510)/106.405

= 27.86 knots

## Answer This Question

## Related Questions

- Calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...
- Calculus - At noon, ship A is 50 nautical miles due west of ship B. Ship A is ...
- calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...
- calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...
- calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...
- calculus - At noon, ship A is 30 nautical miles due west of ship B. Ship A is ...
- CALCULUS - At noon, ship A is 40 nautical miles due west of ship B. Ship A is ...
- Calculus - At noon, ship A is 20 nautical miles due west of ship B. Ship A is ...
- Calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...
- Calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...

More Related Questions