Homework Help Forum: Calculus BC

Posted by Karen on Thursday, October 29, 2009 at 2:20am.

Can someone help me differentiate this? f(x)= 2cos(5 ln(x)) So what is f'(x)?

• Calculus BC - MathMate, Thursday, October 29, 2009 at 7:36am

  You'll need the chain rule, which says dy/dx = dy/du . du/dx Set 5ln(x) as u, then you proceed with f'(x) = 2cos(u).du/dx noting that d(ln(x))/dx = 1/x Can you take it from here?

  
  

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