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Physics-circular force

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A coin is placed 11.0 cm from the axis of a rotating turntable of variable speed. When the speed of the turntable is slowly increased, the coin remains fixed on the turntable until a rate of 31 rpm is reached, at which point the coin slides off. What is the coefficient of static friction between the coin and the turntable?

  • Physics-circular force -

    forcefriction=mg*mu
    centripetalforce= mw^2r
    w= 31*2PIr/60 in rad/sec
    set them equal, solve for mu.

  • Physics-circular force -

    i got 3.64 but that is wrong because it is too large

  • Physics-circular force -

    I didn't get that, I get on the order of .1

    Check your work, or post it here.

  • Physics-circular force -

    mu*9.8=(((30/60)(2pi11))^2)/11
    mu=11.8

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