Tuesday

October 21, 2014

October 21, 2014

Posted by **Angela** on Wednesday, October 28, 2009 at 1:45am.

- Physics -
**Phanor**, Tuesday, October 7, 2014 at 8:10pmFirst draw a free-body-diagram with Fn (normal force) pointing upward mg(Fg) pointing downward and the force of friction Ff to the left. Then set your axis for this problem I choice up and to the left as positive.

So you use Newtons 2nd law to find Fn

So the summation of Fy=ma

Since there is no motion in the y direction a=0

So it is Fg-ma so it's Fg=ma and it's (1500)(10) which gives you 15000N

Then you find Ff

Ff=u(mew)Fn

Ff=(.5)(15000)

Ff=7500N

Then you use F=ma because you are trying to find acceleration in the x direction which means you have to use the Ff because it is in the x direction so you get :

A=Ff/m

A=5 m/s^2

Then you need to find the initial velocity Vi so use

Vf^2=Vi^2 + 2ad

Vf=0 because it skids to rest so

0=Vi^2 + 2ad

-2ad=Vi^2

When you work all of it out you get -25.5 m/s it something around there

Hope this helped

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