Homework Help Forum: calculus

Posted by Anonymous on Tuesday, October 27, 2009 at 11:46pm.

Differentiate the following function. y = (5 x^2 + 7 x + 6)/sqrt(x)

• calculus - digforbear, Wednesday, October 28, 2009 at 12:03am

  use the quotient rule h(x)=ƒ(x)/g(x) h&prime(x)=[ƒ &prime (x)*g(x) - g&prime (x)*ƒ (x)]/g(x)2

  
  

• calculus - Reiny, Wednesday, October 28, 2009 at 12:05am

  You could use the quotient rule, but why not try this approach y = (5 x^2 + 7 x + 6)/sqrt(x) = 5x^(3/2) + 7x^(1/2) + 6x^(-1/2) now dy/dx = (15/2)x^(1/2) + (7/2)x^(-1/2) - 3x^(-3/2) = (1/2)x^(-3/2)[15x^2 + 7x - 6] = (15x^2 + 7x - 6)/(2x√x) check my algebra carefully.

  
  

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