Posted by Sasha on Tuesday, October 27, 2009 at 10:23pm.
almost 2 feet in width
first 121 km/h (1000m/1km)(1h/3600s) = 33.6 m/s
vf2 = vi2 + 2a(&Delta x)
&Delta x is what we want to solve for, it tells us the distance which we will compress the barrier so it needs to be atleast that thick
a is the max acceleration given which I don't really understand from what you've written (-3.0 102?)
vf is 0 because the car will stop
vi is 33.6 m/s
solving for &Delta x we get
[vf2 - vi2] / 2a = &Delta x
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