Posted by **drew** on Tuesday, October 27, 2009 at 9:05pm.

A particle moves in the plane along the curve y=xln(x). At what rate is the distance from the origin increasing at the moment its x-coordinate is 2 cm and its x-coordinate is increasing at a rate of 17 cm/sec?

## Answer This Question

## Related Questions

- college calculus - 1) each side of a square is increasing at a rate of 6cm/s. At...
- Calculus - A particle moves along the curve y = sqr(1+x^3). As it reaches the ...
- Calculus - A particle moves along the curve y = sqr(1+x^3). As it reaches the ...
- calculus - A particle moves along the curve y=square sqrt 1+x^3. As it reaches ...
- Calculus - A point moves along the curve y=(x-2)^2 such that the x coordinate ...
- Calculus - A particle is moving along the curve . As the particle passes through...
- Calculus - A particle is moving along the curve . As the particle passes through...
- Calculus - A particle is moving along the curve . As the particle passes through...
- calculus - A particle is moving along the curve y=4((3x+1)^.5). As the particle ...
- Calculus - A particle is moving along the curve whose equation is (xy^3)/(1+y^2...

More Related Questions