Homework Help Forum: Calculus

Posted by sh on Tuesday, October 27, 2009 at 7:11pm.

At what points on the curve y=(x^2)/(2x+5) is the tangent line horizontal? y'=[(2x)(2x+5)-(2)(x^2)]/(2x+5)^2 =[2x^2+10x]/(2x+5)^2 I plugged 0 into x, and got the coordinates (0,0). How do I get the other pair of coordinates? Thanks in advance.

• Calculus - jim, Tuesday, October 27, 2009 at 7:15pm

  Just from looking at 2x^2+10x and that has to be zero - I'd try -5

  
  

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