An electrical device with a resistance of 323.0 k(omega sign) will allow a current of 21.0 A to flow through it if a voltage drop of _______________ Volts is impressed across the device.
To find the voltage drop across an electrical device, you can use Ohm's law, which states that voltage (V) equals current (I) multiplied by resistance (R), represented by the equation V = I x R.
In this case, you know the resistance (R) is 323.0 kΩ (kilo-ohms) and the current (I) is 21.0 A (amperes). To find the voltage drop, simply substitute the given values into the equation:
V = I x R
V = 21.0 A x 323.0 kΩ
To perform the calculation, you need to convert kilo-ohms (kΩ) to ohms (Ω) since the standard unit for resistance is ohms. One kilo-ohm is equal to 1000 ohms, so:
V = 21.0 A x (323.0 kΩ x 1000 Ω/kΩ)
Now you can perform the multiplication to determine the voltage drop:
V = 21.0 A x 323,000 Ω
V = 6,783,000 V
Therefore, the voltage drop across the device will be 6,783,000 Volts.
It's worth noting that a voltage drop of 6,783,000 Volts is an extremely high value and may not be practically achievable or safe in most electrical systems. This is just a mathematical calculation based on the given values and Ohm's law. In real-world scenarios, the voltage drop would depend on the limitations of the electrical system and the available power supply.