What is the change in thermal energy of water in a pond with a mass of 1,000kg and a specific heat of 4,184j(kgdegreesc) if the water cools by 1 degree c
To calculate the change in thermal energy of water, you can use the formula:
ΔQ = m * c * ΔT
Where:
ΔQ is the change in thermal energy (in joules),
m is the mass of the water (in kilograms),
c is the specific heat of water (in joules per kilogram degrees Celsius), and
ΔT is the change in temperature (in degrees Celsius).
In this case, the given values are:
m = 1,000 kg (mass of water)
c = 4,184 J/(kg·°C) (specific heat of water)
ΔT = -1 °C (change in temperature, with a negative sign indicating cooling)
Now, you can substitute these values into the formula to calculate the change in thermal energy:
ΔQ = 1,000 kg * 4,184 J/(kg·°C) * (-1 °C)
= -4,184,000 J
Therefore, the change in thermal energy of the water in the pond is -4,184,000 joules (J).