Sunday
April 20, 2014

Homework Help: Dr.Bob222

Posted by Brittany on Tuesday, October 27, 2009 at 11:43am.

this is all my work so far on the limiting reagent problem I asked about yesterday about Calcium nitrate and ammonium fluoride....

28.42g/164.1= .17318 mol Ca(NO3)2

29.6g/37.042=.79909 mol (NH4)F

(1mol Ca(NO3)2 /.17318) x (2mol (NH4)F/x)=.34636

(2 mol (NH4)F/.79909)x(1 mol Ca(NO3)2/x)=.399545

so (NH4)F (.34636) is limiting reagent.

now I'm stuck. Not sure what you mean about subtracting moles from initial moles etc.....thanks!

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry HELP ME!!!! - A sloution of calcium nitrate, C(NO3), reacts with a ...
Chemistry 120 - A sloution of calcium nitrate, C(NO3), reacts with a solution of...
Chemistry - Calcium nitrate and ammoonium fluoride react to form calcium ...
Chem - Calculate the concentration of NH4+ from ammonium chloride required to ...
chemistry - 2Na3PO4 + 3CaCl2 ----> Ca3 (PO4)2 + 6NaCl how many moles of CaCl2...
chemistry - 1) All of the following are oxidation-reduction reactions except (a...
CHEM - Please help me, i don't know how to approach this question! All ammonium ...
Chemistry - a class reacts 50.00ml samples of 0.200 mol/L potassium phosphate ...
Chemistry - [6 points] You need to make a solution of Ca(NO3)2 for a class ...
Chemistry - For the following chemical reaction, what mass of silver nitrate in ...

Search
Members