Posted by Josie on Tuesday, October 27, 2009 at 6:27am.
I need help solving these three problems.
1/4(7 + 3g) + -g/8
Twice the greater of two consecutive odd integers is 13 less than three times the lesser number. Find the integers.
About 4.9 million households had one brand of personal computers in 2001. The use of these computers grew at an average rate of 0.275 million households a year. In 2001, about 2.5 million households used another type of computer. The use of these computers gew at an average rate of 0.7 million households a year. How long will it take for the two types of computers to be in the same number of households?
Algebra - Reiny, Tuesday, October 27, 2009 at 8:03am
For the first one, are you simplifying?
1/4(7 + 3g) + -g/8
= (7+3g)/4 - g/8
= (14 + 6g)/8 - g/8
= (14 + 5g)/8
For the second, solve
2(x+2) = 3x - 17
For the third, let t=0 correspond with the year 2001
so C1 = .275t + 4.9
and C2 = .7t + 2.5
Now equate C1 and C2
.275t+4.9 = .7t+2.5
275t + 4900 = 700t + 2500
2400 = 425t
t = 5.6 yrs.
Answer This Question
More Related Questions
- algebra - Twice the greater of two consecutive odd integers is 13 less than ...
- math - Twice the greater of two consecutive odd integers is 13 less than three ...
- algebra - Five times the smallest of three consecutive odd integers is ten more ...
- math - A. Four times one odd integer is 14 less than three times the next even ...
- Math Algebra - Two times the smallest of three consecutive odd integers is one ...
- math - A. In 1 year Kristen will be four times as old as Danielle. Ten years ...
- Algebra 2 - Find three consecutive odd positive integers such that 3 times the ...
- algebra - If the first and third of three consecutive odd integers are added, ...
- Algebra - The sum of the squares of the largest and smallest of three ...
- math - Find three consecutive odd integers such that twice the sum of the first ...