gunpowder is a mixture of potassium nitrate , sulfur and carbon in th proportion (by mass) of 6:1:1 (KNO3;S:C). A typical riflr shell contains 3.2 gunpowder. How many moles of each compnent are there in our sample gunpowder?
KNO3 mole:
C: mol
S: mol
Thank you for helping!!
You omitted the units of 3.2? Is that 3.2 grams? If so, read on. If not, the following is not correct.
So you have 6 + 1 + 1 total = 8 parts of which 6/8 is KNO3, 1/8 is C and 1/8 is S.
3.2 x (6/8) = 2.4 grams KNO3.
3.2 x (1/8) = 0.4 grams S.
3.2 x (1/8) = 0.4 grams C.
Now convert to moles. moles = grams/molar mass.
How do I convert 2.3grams of carbon to particles
To calculate the number of moles of each component in the sample of gunpowder, we will need to convert the given mass ratio into moles.
1. Calculate the molar mass of each component:
- Potassium nitrate (KNO3): The molar mass of K is 39.10 g/mol, N is 14.01 g/mol, and O is 16.00 g/mol. Therefore, the molar mass of KNO3 is (39.10 + 14.01 + (3 × 16.00)) g/mol = 101.10 g/mol.
- Sulfur (S) has a molar mass of 32.06 g/mol.
- Carbon (C) has a molar mass of 12.01 g/mol.
2. Now, let's calculate the number of moles for each component:
- For potassium nitrate (KNO3): Since the ratio is 6:1:1 (KNO3:S:C) by mass, and the total mass of the gunpowder is 3.2 g, the mass of KNO3 in the sample is (6/8) × 3.2 g = 2.4 g. Therefore, the number of moles of KNO3 is (2.4 g ÷ 101.10 g/mol) mol.
- For sulfur (S): The mass of sulfur in the sample is (1/8) × 3.2 g = 0.4 g. Hence, the number of moles of sulfur is (0.4 g ÷ 32.06 g/mol) mol.
- For carbon (C): The mass of carbon in the sample is also (1/8) × 3.2 g = 0.4 g. So, the number of moles of carbon is (0.4 g ÷ 12.01 g/mol) mol.
Calculating these values gives us:
- Moles of KNO3: (2.4 g ÷ 101.10 g/mol) ≈ 0.0237 mol.
- Moles of S: (0.4 g ÷ 32.06 g/mol) ≈ 0.0125 mol.
- Moles of C: (0.4 g ÷ 12.01 g/mol) ≈ 0.0333 mol.
So, the answer to your question is:
- KNO3 mole: Approximately 0.0237 mol
- C mole: Approximately 0.0333 mol
- S mole: Approximately 0.0125 mol