On a worksheet we got, we have to balance out chemical reaction equations then define what kind of reaction it is (synthesis, decomposition, single/double-replacement). Would someone be willing to check my answers, please? Thanks!!

1. c) BaO + H2O ==> ________ (synthesis)

==> For this, I put the product to be BaH2O2.

3. c) H2SO4 + KOH ==> ________ (double-replacement)

==> For this, I put the product to be H2OH + KOSO4, but this doesn't sound right at all. :-/

4. a) CH4 + O2 ==> CO2 + H2O

==> This reaction looks like it could be a double-replacement reaction, but I'm not entirely sure. Anyone have a guess?

1. c) BaO + H2O ==> ________ (synthesis)

==> For this, I put the product to be BaH2O2.
BaH2O2 is correct but I would write is as Ba(OH)2 to make it more recognizable. Synthesis is correct.

3. c) H2SO4 + KOH ==> ________ (double-replacement)

==> For this, I put the product to be H2OH + KOSO4, but this doesn't sound right at all. :-/
You're right. It doesn't sound right nor does it look right. Double displacement is ok. In a double displacement, just switch + and - ions. So K goes with SO4 and H goes with OH. Now you can worry about what the formula for these compounds is. K and SO4 must be K2SO4 while H and OH must be HOH or H2O. I think you are making a mistake in trying to make the formula match the number of atoms and that isn't the way to do it. First, you switch ions. Second you determine the formula (using valences or the periodic table and not the number of atoms). Third, and final step is to balance.
H2SO4 + KOH ==> K2SO4 + H2O
Now balance it.
H2SO4 + 2KOH ==> K2SO4 + 2H2O
(Some would call this an acid/base reaction.)


4. a) CH4 + O2 ==> CO2 + H2O

==> This reaction looks like it could be a double-replacement reaction, but I'm not entirely sure. Anyone have a guess?
You don't have it listed in the preamble of your question but this is a combustion reaction. Also, it is an oxidation-reduction (redox) reaction.

Ohhhh, I think I get what you mean. Thanks!! :)

Sure! I'd be happy to help you check your answers and guide you on how to balance chemical reaction equations and determine the type of reaction.

1. Balanced equation: BaO + H2O -> Ba(OH)2
To balance this equation, we need to ensure that the number of atoms on both sides of the reaction are the same. In this case, we have one barium (Ba) atom on both sides, one oxygen (O) atom on both sides, and two hydrogen (H) atoms on the right side. So, the balanced equation for this synthesis reaction is BaO + H2O -> Ba(OH)2.

2. Balanced equation: H2SO4 + 2KOH -> K2SO4 + 2H2O
To balance this equation, we need to ensure the number of atoms on both sides of the reaction are the same. In this case, we have two hydrogen (H) atoms on both sides, one sulfur (S) atom on both sides, four oxygen (O) atoms on both sides, and two potassium (K) atoms on the right side. So, the balanced equation for this double-replacement reaction is H2SO4 + 2KOH -> K2SO4 + 2H2O.

3. Balanced equation: CH4 + 2O2 -> CO2 + 2H2O
To balance this equation, we need to ensure the number of atoms on both sides of the reaction are the same. In this case, we have one carbon (C) atom on both sides, four hydrogen (H) atoms on both sides, and four oxygen (O) atoms on both sides. So, the balanced equation for this combustion reaction is CH4 + 2O2 -> CO2 + 2H2O.

In conclusion:
- Question 1: The balanced equation is BaO + H2O -> Ba(OH)2, and this is indeed a synthesis reaction.
- Question 2: The balanced equation is H2SO4 + 2KOH -> K2SO4 + 2H2O, and this is a double-replacement reaction.
- Question 3: The balanced equation is CH4 + 2O2 -> CO2 + 2H2O, and this is a combustion reaction.

Remember, when balancing equations, start by balancing the elements that appear in only one compound on each side of the equation. Then, balance the atoms that appear in multiple compounds. Finally, make sure the total number of atoms is the same on both sides of the equation.

I hope this helps! Let me know if you have any more questions.