If you mix KC2H3O2 and BaCl2 what is the molecular equation? There is a reaction because I did the experiment in class and the result was a white cloudy liquid but no precipitate.
I got 2 KC3H3O2 (aq) + BaCl2 (aq) --> 2 KCl (aq) + Ba(C2H3O2)2 (aq) but I don't know if it is correct. My teacher just gives examples and doesn't explain how to do this.
I have a hard time believing you got a reaction.
Your equation is correct if you change the first reactant to KC2H3O2 and it is balanced as written; however, I still don't believe there is a reaction.
To determine the correct molecular equation for the reaction between KC2H3O2 and BaCl2, we need to consider the solubility of the compounds and the possible formation of precipitates.
Let's break down the compounds first:
1. KC2H3O2: This is potassium acetate, which is a soluble compound.
2. BaCl2: This is barium chloride, which is also soluble.
Since both compounds are soluble, it means they dissociate into ions when in aqueous solution. Thus, the complete ionic equation would be:
2 K+ (aq) + 2 C2H3O2- (aq) + Ba2+ (aq) + 2 Cl- (aq) → 2 K+ (aq) + 2 Cl- (aq) + Ba2+ (aq) + 2 C2H3O2- (aq)
However, in the given situation where you observed a white cloudy liquid but no precipitate, it indicates that there is a reaction occurring, but there is no formation of a solid precipitate. So, we can rewrite the equation as:
2 K+ (aq) + 2 C2H3O2- (aq) + Ba2+ (aq) + 2 Cl- (aq) → 2 K+ (aq) + 2 Cl- (aq) + Ba(C2H3O2)2 (aq)
Your proposed equation, 2 KC3H3O2 (aq) + BaCl2 (aq) → 2 KCl (aq) + Ba(C2H3O2)2 (aq), is almost correct. However, the formula for potassium acetate is KC2H3O2, not KC3H3O2.
So, the correct molecular equation for the reaction is:
2 KC2H3O2 (aq) + BaCl2 (aq) → 2 KCl (aq) + Ba(C2H3O2)2 (aq)
To determine the correct molecular equation for the reaction between KC2H3O2 and BaCl2, you need to consider the dissociation of the compounds into their respective ions. Here's how you can obtain the molecular equation:
1. Write out the chemical formulas for the reactants:
KC2H3O2 (potassium acetate) + BaCl2 (barium chloride)
2. Identify the ions that each compound dissociates into when they are dissolved in water. Potassium acetate dissociates into potassium ions (K+) and acetate ions (C2H3O2-), while barium chloride dissociates into barium ions (Ba2+) and chloride ions (Cl-):
KC2H3O2(aq) → K+(aq) + C2H3O2-(aq)
BaCl2(aq) → Ba2+(aq) + 2Cl-(aq)
3. Now, combine the ions to form the products of the reaction. Here, the positive ion (potassium ion) from the first compound combines with the negative ion (chloride ion) from the second compound, and vice versa. This results in potassium chloride (KCl) and barium acetate (Ba(C2H3O2)2):
K+(aq) + Cl-(aq) → KCl(aq)
Ba2+(aq) + 2C2H3O2-(aq) → Ba(C2H3O2)2(aq)
4. Finally, write the overall balanced equation by combining the reactants and the products:
2 KC2H3O2(aq) + BaCl2(aq) → 2 KCl(aq) + Ba(C2H3O2)2(aq)
Based on the information provided, your initial attempt at the molecular equation appears to be correct. However, it is always essential to double-check and balance the equation properly.